# What is a solution to the differential equation #y'=1/2sin(2x)#?

##### 2 Answers

Mar 26, 2018

Question makes no sense

#### Explanation:

You can't solve or simply such an equation do you mean differentiate the equation?

Then you have to chain rule it

So now you multiply the two derivatives together

Mar 26, 2018

# y = -1/4cos(2x) + C #

#### Explanation:

We have:

# dy/dx = 1/2sin(2x) #

This is a First Order Separable ODE, so we can *"separate the variables"* .

# int \ dy = int \ 1/2sin(2x) \ dx #

Both integrals have well known trivial result so we can immediately integrate to get:

# y = 1/2(-cos(2x)/2) + C #

# :. y = -1/4cos(2x) + C #